Arithmetic 6: Digit Recreations

1. 100 = [1 / (2^3 \times \sqrt{4})] \times [5 / (6 \times 7)] \times [8! / \sqrt{9}].

2. 99 = (12! \times 3) / (4 \times 5 \times 6 \times 7! \times 8 \times \sqrt{9}).

3. 100 = \left(\sqrt{\sqrt{8 + \sqrt{\sqrt{8 + 8}}}}\right)^8.

4. 100 = [(3!)! - ((3!)! / 3!)] / 3!.

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