# Arithmetic 6: Digit Recreations

1. 100 = $[1 / (2^3 \times \sqrt{4})] \times [5 / (6 \times 7)] \times [8! / \sqrt{9}]$.

2. 99 = $(12! \times 3) / (4 \times 5 \times 6 \times 7! \times 8 \times \sqrt{9})$.

3. 100 = $\left(\sqrt{\sqrt{8 + \sqrt{\sqrt{8 + 8}}}}\right)^8$.

4. 100 = $[(3!)! - ((3!)! / 3!)] / 3!$.